WebMar 30, 2024 · Here in this question, we are given that the nth term of the sequence is $ {T_n} = 128 $ and the sum of n terms is $ {S_n} = 255 $ . Also, the common ratio of the sequence $ r = 2 $ . And we are asked to find the first term of the sequence. We will use the formula for the sum of n terms of a G.P to get the first term. WebJan 26, 2024 · 10 t h. of the G.P. 5, 25, 125 and so on will be. 5 10. . This is the required answer. Note: Whenever we are given a sequence, we always have to first check if the sequence is in Arithmetic progression (AP) or in Geometric progression (GP). The GP will have the common ratio and the AP will have the common difference between the two …
Nth term of GP Geometric Progression Solved …
WebMar 30, 2024 · Example 9 Find the 10th and nth terms of the G.P. 5, 25,125, . 5, 25,125, We know that an = arn 1 where an = nth term of GP n is the number of terms a is the first term r is the common ratio Here, first term a = 5 , common ratio r = 25/5 = 5 Now, nth term of GP = an = arn 1 = 5 (5)n 1 = 51 5n 1 = 51 + n 1 = 5n Hence, nth term of G.P. = 5n For … WebTo find the n th term of a GP, we require the first term and the common ratio. If the common ratio is not known, the common ratio is calculated by finding the ratio of any term to its … can pineapple help with digestion
Formulas for AP and GP and HP AP and GP and HP PrepInsta
WebProperties of Geometric Progression. If ‘a’ is the first term, r is the common ratio of a finite G.P. consisting of m terms, then the nth term from the end will be = a rm-n. Reciprocal of all the term in G.P are also considered in the form of G.P. When all terms is GP raised to same power, the new series of geometric progression is form. WebJul 7, 2024 · If first and nth term of a GP are a and b respectively, and if P is the product of n terms, prove that P^2=(ab)^n. WebIf p th term of a G. P. is P and its q th term is Q. Prove that the n th term is (Q n−pp n−q) p−q1 Medium Solution Verified by Toppr We have pth term, a p=p ⇒ar p−1=p ⇒a= r p−1p ..... (1) qth term, a q=q ⇒ar q−1=p ⇒a= r q−1q ..... (2) From (1) and (2) r p−1p = r q−1q ∴r=(qp) p−q1 From (1) a= ⎣⎢⎢⎡(qp) p−q1 ⎦⎥⎥⎤p−1p =(q 1−pp 1−q) p−q1 nth term flametech new castle de